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Synchronous Machines - 5. Exercise 2
SYNCHRONOUS GENERATOR, NOT CONNECTED TO THE GRID, FEEDING A PASSIVE LOAD
Section Content
5.1 Objective
This exercise presents the implementation of the synchronous machine operating as an autonomous generator, not connected to an AC grid and supplying a balanced, three-phase passive load.
When the passive load varies, the output frequency of the synchronous generator is kept constant at its nominal value by adjusting the DC motor speed.
We are performing two load tests for different power factors: (i) a purely resistive load at unity power factor, and (ii) inductive and capacitive load at power factor equal to 0.7.
The first test is performed with a constant field current and shows the evolution of the synchronous generator load's voltage drop on a variable passive load with a constant power factor.
In the second test, we maintained a constant generator output voltage by varying the field current when the load varies.
Thus, we will get the current regulation curves of the synchronous generator's field that keeps a constant output voltage on a variable passive load with a power factor applied.
These regulation curves can be used to sizing the generator field's power source voltage.
The results obtained serve to analyze the generator's exchange of Q with the passive load.
The tests are also used to validate the synchronous machine's steady state model, whose parameters were determined using the low power test from Exercise 1.
5.2 Initialization of the Setup
When the simulator is started up, the initial settings on screen are as follows:
- Continuous voltage supplies SC1, SC2, SC3 set to 0 V.
- Continuous voltage supply SC4, in the "Measurement Resistors" tab, set to 0 V.
- Alternative power SA1, in the tab "AC Grid" tab, set to 0 V.
- Switches K1, K2, K3, K4 opened: synchronous generator armature has no load. See Table 4.
- Switch K6 disabled: the synchronous machine rotor is driven by the DC motor. See Table 4.
- Switch K5 disabled: voltage source SC3 powers the synchronous machine field winding. See Table 4.
- Trigger switches K10, K11, K12, K13, K14, in the tab "Oscilloscope", disabled. See Table 4.
5.3 Description of the RLC Passive Load
This is a passive series RLC, three-phase, wye-configured, balanced load that can be connected to the synchronous generator's stator (see Fig.10).
The complex impedance Z per phase at 60 Hz is variable and the user can independently adjust the resistive, inductive and capacitive components using R, XL and XC settings. (Z=R+j(XL-XC)).
By controlling R, XL and XC settings, we can also modify the power factor value displayed in the "Load RLC" tab.
Note that the XL, XC and the power factor values are only valid when the synchronous generator's frequency output is 60 Hz.
The minimum setting values for R, XL (60Hz) and XC (60Hz) are 10 Ω, 5 Ω and 5 Ω respectively, and the maximum values are equal to 300 Ω. The overall reactance value is: X = XL-XC.
5.4 Test of the Synchronous Generator Feeding a Resistive Load
5.4.1 Setup Diagram
Figure 10: Diagram of the synchronous generator driven by the DC motor and supplying the passive RLC load
In this exercise, the synchronous machine is operating in generator mode and is driven by the DC motor.
Use sources SC1 and SC2, as described in Section 4.3, to control the generator drive speed and the armature output voltage frequency.
The synchronous generator is feeding a passive RLC load. Switch K3 is closed.
This is a load test: the synchronous generator converts the mechanical power supplied to its shaft by the DC motor, into electrical power that is dissipated by the load and the losses.
5.4.2 Exercise
- Reset the setup to its original state, as described in Section 5.2 by bringing voltage sources SC3, SC1 and SC2 back to 0 and resetting switches to their default conditions.
Thus, the synchronous machine's rotor is driven by the DC machine, switch K5 is disabled and the voltage source SC3 supplies the synchronous machine's field winding.
Select the "RLC load" tab in the panel. - Follow the procedure described in Section 4.3 of Exercise 1 to start the DC motor and set the drive speed to 1800 rpm so that the generator's output voltage frequency is 60 Hz.
- Adjust the synchronous machine current field Jf with the voltage source SC3 so that the RMS line-line value of the armature is Us= 460 V at 1800 rpm with no load.
- Close switch K3 to connect the RLC load to the synchronous machine armature's winding.
During this resistive load exercise, the inductive reactance value XL and the capacitive reactance Xc must be adjusted to 5Ω (XL-XC =0) for the duration of the test.
Thus Z=R+j(XL-XC)=R, the load is resistive, and its power factor is unitary.
In this case, we can adjust Is from 0 to Isn varying the resistance R from 300 Ω to 10 Ω. - Without changing current Jf adjusted in step c and by maintaining constant speed and frequency using SC2, gradually vary the resistance so that Is varies from 0 to Isn.
For each steady state operating point, take note of the values of the line-line RMS voltage Us and the RMS current Is.
It is important to maintain a constant frequency or the test results will be unusable.
Calculate the RMS line-neutral voltage Vs for each operating point and determine the characteristic Vs vs Is at constant frequency and field current on a resistive load. - Disconnect the RLC load using switch K3.
Reset the setup to its original state described in Section 5.2. - Repeat steps 1 to 4 then, starting with step 5, adjust the value of Jf using SC3 at each new R and Is value to compensate the voltage drop and maintain a constant generator RMS voltage output value equal to Us = 460 V.
Make sure to maintain constant speed (1800 rpm) and frequency (60 Hz) using SC2, otherwise the test results will be unusable.
Thus, we obtain the synchronous generator's field current regulation curve Jf vs Is which maintains a constant voltage on a variable resistive load.
Take note of the regulation curve Jf vs Is until the nominal value for Isn. - Disconnect the RLC load using switch K3.
Reset the setup to its original state described in Section 5.2.
5.5 Test of the Synchronous Generator Feeding an Inductive Load
The wye-connected passive load, as in the previous exercise, is now a variable inductive load that absorbs active and reactive power (the load is studied as receptor convention, so the current phasor Is lags the line neutral voltage Vs).
When this load varies, we must maintain the frequency at 60 Hz and the power factor constant at 0.707.
In this case, we use this procedure:
- Set the capacitive reactance Xc to its minimum value of 5 Ω and maintain this value throughout the test.
- Vary resistance R and inductive reactance XL to adjust the module of the complex impedance Z and modify the current Is from 0 to Isn while keeping the constant power factor at 0.707.
To maintain the power factor value, note that Z=R+j(XL-XC)= R+jX.
Thus, it is sufficient to vary R and XL so that R = X = XL-XC (example: R= 295 Ω, XL = 300 Ω and XC = 5 Ω, which gives R = XL-XC = 300 – 5 = 295 Ω)
5.5.1 Exercise
- Return to the initial state, as described in Section 5.2 by bringing voltage sources SC3, SC1 and SC2 back to 0 and resetting switches to their default conditions. Thus, the synchronous machine's rotor is driven by the DC motor, switch K5 is closed and the voltage source SC3 supplies the synchronous machine's field winding. Switch K3 is open. Select the "RLC load" tab in the panel.
- Follow the procedure described in Section 4.3 of Exercise 1 to start the DC motor and set the drive speed to 1800 rpm so that the generator's output voltage frequency is 60 Hz.
- Adjust the synchronous machine current field Jf with the voltage source SC3 so that the RMS line-line value of the armature is Us= 460 V at 1800 rpm with no load.
- Close switch K3 to connect the RLC load to the synchronous machine armature's winding. During this test on an inductive load, it is necessary to adjust resistance R and reactive inductance XL to modify the complex impedance module Z and vary the current Is from 0 to Isn, while keeping a constant power factor of 0.707 at 60 Hz. Use the passive load adjusting method described in Section 5.5 to achieve this.
- Without changing current Jf adjusted in the step c, and maintaining constant speed and frequency using SC2, gradually vary the resistance R and inductive reactance XL so that Is varies from 0 to a value as close as possible to the nominal Isn, while keeping a constant power factor of 0.707 at 60 Hz. For each steady state operating point, take note of the RMS value of the line-line voltage Us and the RMS value of the current Is. It is important to maintain a constant frequency, otherwise the test results will be unusable. For every point calculate the RMS line-neutral voltage Vs value and determine the characteristics Vs Is at constant frequency and field current on an inductive load with a power factor of 0.707.
- Disconnect the RLC load using switch K3. Reset the setup to its original state described in Section 5.2.
- Repeat steps a to d, then, starting with step e, adjust the value of Jf using SC3 at each new R, XL and Is value to compensate the voltage drop and maintain a constant generator RMS voltage output value equal to Us = 460 V. Make sure to maintain constant speed (1800 rpm) and frequency (60 Hz) using SC2, otherwise the test results will be unusable. Thus, we obtain the synchronous generator's field current regulation curve Jf vs Is which maintains a constant voltage on a variable inductive load. Take note of the regulation curve Jf vs Is until the closest value to the nominal Isn is reached.
- Reset the setup to its original state described in Section 5.2 by bringing voltage sources back to 0 and disabling all switches.
5.6 Test of the synchronous generator feeding a capacitive load
The wye-connected passive load, as in the previous exercise, is now a variable capacitive load that absorbs active power and produces reactive power (the load is studied as receptor convention, so the current phasor Is leads the line neutral voltage Vs). When this load varies, we must maintain the frequency at 60 Hz and the power factor constant at 0.707. In this case, we use this procedure:
- Set the capacitive reactance XL to its minimum value of 5 Ω and maintain this value throughout the test.
- Vary the resistance R and capacitive reactance XC to adjust the module of the complex impedance Z and to modify the current Is from 0 to Isn while keeps constant power factor at 0.707. To maintain the power factor value, note that Z=R+j(XL-XC)= R+jX. Thus, it is enough to vary R and XC so that R = -X = XC-XL (example: R= 295 Ω, XC = 300 Ω and XL = 5 Ω, which gives R = XC-XL = 300 – 5 = 295 Ω)
5.6.1 Exercise
- Return to the initial state, as described in Section 5.2, by bringing voltage sources SC3, SC1 and SC2 back to 0 and resetting switches to their default conditions.
Thus, the synchronous machine's rotor is driven by the DC motor, switch K5 is closed and the voltage source SC3 supplies the synchronous machine's field winding.
Switch K3 is open.
Select the "RLC load" tab in the panel. - Follow the procedure described in Section 4.3 of Exercise 1 to start the DC motor and set the drive speed to 1800 rpm so that the generator's output voltage frequency is 60 Hz.
- Adjust the synchronous machine current field Jf with the voltage source SC3 so that the RMS line-line value of the armature is Us= 460 V at 1800 rpm with no load.
- Close switch K3 to connect the RLC load to the synchronous machine armature's winding.
During this test on a capacitive load, it is necessary to adjust resistance R and reactive inductance XC to modify the complex impedance module Z and vary the current Is from 0 to a value as close as possible to the nominal Isn, while keeping a constant power factor of 0.707 at 60 Hz.
Use the passive load adjusting method described in Section 5.6 to achieve this. - Without changing current Jf adjusted in the step 3 and maintaining constant speed and frequency using SC2, gradually vary the resistance R and capacitive reactance XC so that Is varies from 0 to a value as close as possible to the nominal Isn, while keeping a constant power factor of 0.707 at 60 Hz.
For each steady state operating point, take note of the RMS value of the line-line voltage Us and the RMS value of the current Is.
It is important to maintain a constant frequency, otherwise the test results will be unusable.
For every point calculate the RMS line-neutral voltage Vs value and determine the characteristics Vs vs Is at constant frequency and field current on an inductive load with a power factor of 0.707. - Disconnect the RLC load using switch K3.
Reset the setup to its original state described in Section 5.2. - Repeat steps 1 to 4 then, starting with step 5, adjust the value of Jf using SC3 at each new R, XC and Is value to compensate the voltage drop and maintain a constant generator RMS voltage output value equal to Us = 460 V.
Make sure to maintain constant speed (1800 rpm) and frequency (60 Hz) using SC2, otherwise the test results will be unusable.
Thus, we obtain the synchronous generator's field current regulation curve Jf vs Is which maintains a constant voltage on a variable capacitive load.
Take note of the regulation curve Jf vs Is until the closest value to the nominal Isn is reached. - Reset the setup to its original state described in Section 5.2 by bringing voltage sources back to 0 and disabling all switches.
5.7 Lab Report
- Present the results in tables (SI units) for all three curves Vs vs Is at constant frequency and field current on: (i) a resistive load with unitary power factor (ii) an inductive load with lagging power factor of 0.707 and (iii) a capacitive load with leading power factor of 0.707.
- Plot all characteristics Vs vs Is on the same graph (SI units).
What can we see with respect to the voltage drop for the current Is = 0.5 Isn?
What can we deduce, in general, about synchronous machine voltage output variations when the load absorbs or produces reactive power while the current field Jf is constant? - Show that if we extrapolate the 3 characteristics Vs vs Is, they converge on point Is=0 for the same voltage value Us.
What does this voltage represent? - Present the results in tables (SI units) for the 3 synchronous machine's current field regulation curves Jf vs Is measured at constant frequency and voltage on: (i) a variable resistive load with unity power factor (ii) a variable inductive load with lagging power factor of .707 and (iii) a variable capacitive load with leading power factor of .707.
- Plot all characteristics Jf vs Is on the same graph (SI units).
For the same current value Is, what do we notice in terms of field current Jf values that are required to maintain a constant Vs for the following three operation points: (i) the load does not have any exchange of reactive power with the synchronous generator (ii) the load consumes reactive power from the synchronous generator, and (iii) the load supplies reactive power to the synchronous generator?
Does this behavior correspond to the curves plotted at step 2? - Using the synchronous machine's steady state model, whose parameters E(Jf), Xd, Xq and Rs were determined using the low power tests of Exercise 1, is it possible to predict and calculate characteristics Vs vs Is and Jf vs Is in this exercise?
Using the theoretical machine model, its parameters and circuit methods learned in the class (Kirchhoff and Ohm's laws, phasor diagram, etc.) determine the expressions of the characteristics Vs vs Is and Jf vs Is for: (i) lagging power factors (ii) unity power factor, and (iii) a leading power factor.
Use these expressions to calculate theoretical characteristics Vs vs Is and Jf vs Is corresponding to this exercise.
To compare these curves, superimpose on a single graph the theoretical calculated and measured characteristics.
What can we deduce about the synchronous machine's steady state model validity?
Discuss. - Show qualitatively, how we can control the RMS voltage of a node connected to an AC grid injecting or absorbing reactive power to/from this node.
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